7c+3=2c^2

Solution for 7c+3=2c^2 equation:

7c+3=2c^2

We move all terms to the left:

7c+3-(2c^2)=0

determiningTheFunctionDomain
-2c^2+7c+3=0

a = -2; b = 7; c = +3;
Δ = b2-4ac
Δ = 72-4·(-2)·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{73}}{2*-2}=\frac{-7-\sqrt{73}}{-4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{73}}{2*-2}=\frac{-7+\sqrt{73}}{-4}
$